I have a win forms application the sets some value to registry.


There is a windows service too to run on the same machine with localsystem account. But when it tries to read the value from registry that the winforms application had set, it gives problem.

RegistryKey RK = objRegistry.OpenSubKey(@"Software\12_0X");

is the code that I've used and getting error(RK is null)





But if I try the code:

RegistryKey RK = objRegistry.OpenSubKey(@"Software");

it returns value..

I checked the path it is correct.. Itried the same code from winforms, it works perfectly...

Please help me in this matter...

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brittogladez

What is objRegistry?

If objRegistry refers to HKEY_CURRENT_USER and your service and app run as different users, then that could explain why one can find the key and the other cannot.

Consider running both service and app as the same user, or store your information under HKEY_LOCAL_MACHINE instead of HKEY_CURRENT_USER. Note, however, that you generally need to be admin to write to HKEY_LOCAL_MACHINE although ordinary users can (usually) read from it.

Thats Perfect!

Now things are up and running. I changed the registry to Local as you suggested

RegistryKey objRegistry = Registry.LocalMachine;



Thanks "BinaryCoder" Thanks MSDN.

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brittogladez

What is objRegistry?

If objRegistry refers to HKEY_CURRENT_USER and your service and app run as different users, then that could explain why one can find the key and the other cannot.

Consider running both service and app as the same user, or store your information under HKEY_LOCAL_MACHINE instead of HKEY_CURRENT_USER. Note, however, that you generally need to be admin to write to HKEY_LOCAL_MACHINE although ordinary users can (usually) read from it.

Ye thats true objRegistry is HKEY_CURRENT_USER. I think this answers my question but any how I'll test this and post the result.

Thank you "BinaryCoder"

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brittogladez

Thats Perfect!

Now things are up and running. I changed the registry to Local as you suggested

RegistryKey objRegistry = Registry.LocalMachine;



Thanks "BinaryCoder" Thanks MSDN.

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brittogladez