Dear,
I have a file "c:\1.exe" when it load, I want him to run another file "c:\my\2.exe", which it calls some references from its path "c:\my".
Please I dont want to use process control for some references reasons. How can I open it directly without using process?
Thx in advanced.

How are you using the Process class?

If you want the "working directory" to be different when you execute a file, you can use the Process.Start(ProcessStartInfo) method and use the ProcessStartInfo.WorkingDirectory property. You can try overriding the working directory to see if that changes things, for example:

Dear,

I have a file in "C:\my" called "2.exe" which load its methods from a DLL called "2.dll" found in the same place. Some of these methods is outpot stream which write some notes to a file in te same location too.

I created another application "1.exe", not in the same location, this application call the "2.exe" application.

If I use Process class, the stream writer right the file on the path of "1.exe" and not the original path of "2.exe" and the methods called by 2.exe from the dll not found.

I want to call the exe file without using process to prevent path mistakes.

Thx

How are you using the Process class?

If you want the "working directory" to be different when you execute a file, you can use the Process.Start(ProcessStartInfo) method and use the ProcessStartInfo.WorkingDirectory property. You can try overriding the working directory to see if that changes things, for example:

Thx alot guys for your help, I will try this asap and seems that it will solve my problem.

I will keep you in touch if not.

Thx