- Edited bywaterding Tuesday, September 22, 2009 11:26 AMmodified
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| | waterding | http:\/\/[\w\.\/\?=\#&+-]*
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com | | JohnGrove | http:\/\/[\w\.\/\?=\#&+-]*
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com
Thanks for your reply. I think I haven't described my question clearly. I actually need a regex to extract the values of parameter 'p' and 'q' from a url, not a regex to validate url. | | waterding | Oh I see, how far should the p= go to in your examples?
[Try this for starters, but I am not sure how far you want it]
String pattern = @"(?:p|q)=[\w+]*";
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com- Edited byJohnGrove Tuesday, September 22, 2009 1:29 PM
- Edited byJohnGrove Tuesday, September 22, 2009 1:39 PM
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| | JohnGrove | Oh I see, how far should the p= go to in your examples?
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com
For example I need to extract 'google+search+engine' from this url http://www.google.co.uk/#hl=en&q=google+search+engine&meta=&fp=2d600fc9f1842146 I need to extract 'banana' from this url http://www.bing.com/search?q=banana&FORM=MSNH90&mkt=en-gb I need to extract 'google+apple' from this url http://uk.search.yahoo.com/search?rd=r1&p=google+apple&toggle=1&cop=mss&ei=UTF-8&fr=yfp-t-702 | | waterding | String pattern = @"(?:p|q)=(?<Word>[\w+]*)";
Regex rx = new Regex(pattern, RegexOptions.IgnoreCase);
Match m = rx.Match(inputStringOfUrls);
while (m.Success)
{
Console.WriteLine(m.Value);
Console.WriteLine(m.Groups["Word"].Value);
Console.WriteLine("");
m = m.NextMatch();
}
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com- Edited byJohnGrove Tuesday, September 22, 2009 1:36 PM
- Edited byJohnGrove Tuesday, September 22, 2009 1:38 PM
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| | JohnGrove | String pattern = "(?:p|q)=(?<Word>[\w+]*)";
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com
Just tried, it's saying that the regular expression contains an error. | | waterding |
String pattern = @"(?:p|q)=(?<Word>[\w+]*)";
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com
Just tried, it's saying that the regular expression contains an error.
Sorry, I forgot the verbatim @
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com | | JohnGrove | String pattern = @"(?:p|q)=(?<Word>[\w+]*)";
Regex rx = new Regex(pattern, RegexOptions.IgnoreCase);
Match m = rx.Match(inputStringOfUrls);
while (m.Success)
{
Console.WriteLine(m.Value);
Console.WriteLine(m.Groups["Word"].Value);
Console.WriteLine("");
m = m.NextMatch();
}
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com
Thanks very much for this. I just tried this url http://www.google.co.uk/#hl=en&q=google+search+engine&meta=&fp=2d600fc9f1842146 It extracts both google+search+engine and 2d600fc9f1842146 . 2d600fc9f1842146 is actually of parameter 'fp', not 'p'. Can you only match 'p' parameter and 'q' parameter. | | waterding | This pattern can do \b[pq]=(.+?)[\&\s] or [?&][pq]=(.+?)[&\s] the value is inside the captured group or you can use look ahead and look behind John, your pattern will also match fp=2d600fc9f1842146 cop=mss so it's not accurate.
www.wonderstudio.cn | | Eping Wang | I am mistaken, I thought the user wanted all where p=[anything] or q=[anything]
Try just adding a boundary on it like so:
String pattern = @"\b(?:p|q)=(?<Word>[\w+]*)";
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com | | JohnGrove | This pattern can do
\b[pq]=(.+?)[\&\s]
or
[?&][pq]=(.+?)[&\s]
the value is inside the captured group
or you can use look ahead and look behind
John, your pattern will also match
fp=2d600fc9f1842146
cop=mss
so it's not accurate.
www.wonderstudio.cn
Not a big deal, simple add the \b to the start of the pattern and that solves that.
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com | | JohnGrove | Yes, all roads to Rome. There're still other patterns can do this work. This is a very good case for learning Regex, I wish to write this case in my website or my blog.
www.wonderstudio.cn | | Eping Wang | Yea, programming is interesting in how the mind works. We can create different solutions to do the same thing.
John Grove - TFD Group, Senior Software Engineer, EI Division, http://www.tfdg.com | | JohnGrove |
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